If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25x^2-49x+18=0
a = 25; b = -49; c = +18;
Δ = b2-4ac
Δ = -492-4·25·18
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{601}}{2*25}=\frac{49-\sqrt{601}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{601}}{2*25}=\frac{49+\sqrt{601}}{50} $
| x–25=96 | | 6^x-3+5=55 | | 3a-80=a | | x.x-25=96 | | -4n+5n=32 | | 35x-10=7x+50 | | 2x4x5=(4x2)x5 | | 2n(3n+7)=8 | | x+44+3x=180 | | 2x+0.3x=x | | 1/3-f=1/112 | | -16s=-18-15s | | 2x+45=5x+18 | | 1/6-n=1/2 | | –16s=–18−15s | | 30x^2+6x-7=0 | | 3=-2v- | | 10-2n=90 | | n-1/6=1/2 | | 12y-1÷2=9y+8÷5 | | 5+x+4=9+2x | | j/4+1=4 | | 360=6t | | x/1+1=x/4-1 | | y÷4=4 | | 4x+3+x+2=180 | | 8+p=52 | | -3+y=40 | | y+-3=40 | | 36−4b=12 | | -5p+4=-6p | | X(2.39)+x(2.49)=46.21 |